Marinel
08-03-2009, 03:50
<div id="div_table">
<?php
$db = mysql_connect ("localhost","root","123456");
mysql_select_db("date",$db);
$result = mysql_query ("SELECT id,code,date FROM korobki",$db);
$myrow = mysql_fetch_array ($result);
do {
echo ("<table width='90%' height='166' border='0' cellpadding='0' cellspacing='0'>
<tr id='table_title'>
<td width='21%' height='12'>код коробки</td>
<td width='23%'>дата добавления</td>
<td width='40%'>количество просмотров</td>
<td width='16%'></td>
</tr>
<tr id='table_text'>
<td height='18'>%s</td>
<td></td>
<td></td>
<td></td>
</tr>
<tr>
<td></td>
<td></td>
</tr>
</table>", $myrow["code"]);
}
while ($myrow = mysql_fetch_array ($result));
?>
</div>
Говорит вот что
Parse error: syntax error, unexpected ',' in S:\home\localhost\www\ritual\catalog.php on line 54
<?php
$db = mysql_connect ("localhost","root","123456");
mysql_select_db("date",$db);
$result = mysql_query ("SELECT id,code,date FROM korobki",$db);
$myrow = mysql_fetch_array ($result);
do {
echo ("<table width='90%' height='166' border='0' cellpadding='0' cellspacing='0'>
<tr id='table_title'>
<td width='21%' height='12'>код коробки</td>
<td width='23%'>дата добавления</td>
<td width='40%'>количество просмотров</td>
<td width='16%'></td>
</tr>
<tr id='table_text'>
<td height='18'>%s</td>
<td></td>
<td></td>
<td></td>
</tr>
<tr>
<td></td>
<td></td>
</tr>
</table>", $myrow["code"]);
}
while ($myrow = mysql_fetch_array ($result));
?>
</div>
Говорит вот что
Parse error: syntax error, unexpected ',' in S:\home\localhost\www\ritual\catalog.php on line 54